(4^4)^3x-5=(4^1)^2x-2

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Solution for (4^4)^3x-5=(4^1)^2x-2 equation: 



(4^4)^3x-5=(4^1)^2x-2

We move all terms to the left:

(4^4)^3x-5-((4^1)^2x-2)=0

We get rid of parentheses

4^4^3x-4^1^2x+2-5=0

We add all the numbers together, and all the variables

4^4^3x-4^1^2x-3=0

We move all terms containing x to the left, all other terms to the right

4^4^3x-4^1^2x=3

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